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x^2=(-7x-2)
We move all terms to the left:
x^2-((-7x-2))=0
We calculate terms in parentheses: -((-7x-2)), so:We get rid of parentheses
(-7x-2)
We get rid of parentheses
-7x-2
Back to the equation:
-(-7x-2)
x^2+7x+2=0
a = 1; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·1·2
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{41}}{2*1}=\frac{-7-\sqrt{41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{41}}{2*1}=\frac{-7+\sqrt{41}}{2} $
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